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Q) lim (𝑦→0) (√(1+√(1+𝑦^4 )) −√2)/𝑦^4#jee #maths #jee2025 #jee2026 #jeemains #mathematics #pyq
JEE MAINS 2019 ( 9 Jan – SHIFT 1 ) Q) lim (𝑦→0) (√(1+√(1+𝑦^4 )) −√2)/𝑦^4 (a) exists and equals 1/(4√2)(b) exists and equals 1/(2√2(√2+1))(c) exists and equals 1/(2√2)(d) does not exist JEE MAIN PYQ 2025 ( 3 April - shift 2 ) Limits and continuity PYQ 2025 #maths Class12 #jee2026 Insta I’d- Shivanggupta34 LIMITS ...
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